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2x + 3 ────────── + x - 4 x - 5 x + 5 - 3 can be written in the form ax + b ─────────── where a and b are integers - Edexcel - GCSE Maths - Question 22 - 2022 - Paper 3

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2x-+-3--──────────-+-x---4-----x---5--x-+-5----3--can-be-written-in-the-form----------ax-+-b--───────────---where-a-and-b-are-integers-Edexcel-GCSE Maths-Question 22-2022-Paper 3.png

2x + 3 ────────── + x - 4 x - 5 x + 5 - 3 can be written in the form ax + b ─────────── where a and b are integers. x² - 25 ... show full transcript

Worked Solution & Example Answer:2x + 3 ────────── + x - 4 x - 5 x + 5 - 3 can be written in the form ax + b ─────────── where a and b are integers - Edexcel - GCSE Maths - Question 22 - 2022 - Paper 3

Step 1

Step 1: Combine the Fractions

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Answer

First, let's rewrite the left-hand side:

rac{2x + 3}{x - 5} + rac{x - 4}{x + 5} - 3

To combine these fractions, we need a common denominator which is ((x - 5)(x + 5) = x^2 - 25).

Step 2

Step 2: Simplify the Expression

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Answer

Rewriting the fractions:

rac{(2x + 3)(x + 5) + (x - 4)(x - 5) - 3(x - 5)(x + 5)}{x^2 - 25}

Expanding each term:

  1. ((2x + 3)(x + 5) = 2x^2 + 10x + 3x + 15 = 2x^2 + 13x + 15)
  2. ((x - 4)(x - 5) = x^2 - 5x - 4x + 20 = x^2 - 9x + 20)
  3. (-3(x^2 - 25) = -3x^2 + 75)

Combine these:

2x2+13x+15+x29x+203x2+752x^2 + 13x + 15 + x^2 - 9x + 20 - 3x^2 + 75

This simplifies to:

(x2+4x+110)(-x^2 + 4x + 110)

Step 3

Step 3: Set Up for a and b

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Answer

We can now express the original fraction as:

x2+4x+110x225\frac{-x^2 + 4x + 110}{x^2 - 25}

This means that:

a = 4

b = 110

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