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A solid cone is joined to a solid hemisphere to make the solid T shown below - Edexcel - GCSE Maths - Question 18 - 2022 - Paper 2

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A solid cone is joined to a solid hemisphere to make the solid T shown below. The diameter of the base of the cone is 7cm. The diameter of the hemisphere is 7cm. Th... show full transcript

Worked Solution & Example Answer:A solid cone is joined to a solid hemisphere to make the solid T shown below - Edexcel - GCSE Maths - Question 18 - 2022 - Paper 2

Step 1

Calculate the value of y.

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Answer

To find the value of yy, we first determine the volume of the solid T, which is comprised of a cone and a hemisphere:

  1. Calculate the radius of the hemisphere and cone:
    The diameter of both the cone and hemisphere is 77 cm, so the radius rr is:
    r=72=3.5 cmr = \frac{7}{2} = 3.5 \text{ cm}

  2. Calculate the volume of the hemisphere (V_h):
    The volume of a hemisphere is given by the formula: Vh=23πr3V_h = \frac{2}{3} \pi r^3 Substituting the radius:
    Vh=23π(3.5)3=23π42.87589.797 cm3V_h = \frac{2}{3} \pi (3.5)^3 = \frac{2}{3} \pi \cdot 42.875 \approx 89.797 \text{ cm}^3

  3. Determine the volume of the cone (V_c):
    The volume of a cone is given by the formula: Vc=13πr2hV_c = \frac{1}{3} \pi r^2 h
    Here, we do not yet know the height hh, but from the total volume of T: 120=Vh+Vc120 = V_h + V_c Vc=120Vh=12089.79730.203 cm3V_c = 120 - V_h = 120 - 89.797 \approx 30.203 \text{ cm}^3
    Therefore: 30.203=13π(3.5)2h30.203 = \frac{1}{3} \pi (3.5)^2 h Simplifying this gives: 30.203=13π12.25h30.203 = \frac{1}{3} \pi \cdot 12.25 h h=30.2033π12.252.37 cmh = \frac{30.203 \cdot 3}{\pi \cdot 12.25} \approx 2.37 \text{ cm}

  4. Calculate the total height y of T:
    The total height of T consists of the height of the cone and the radius of the hemisphere: y=h+r=2.37+3.5=5.87extcmy = h + r = 2.37 + 3.5 = 5.87 ext{ cm}

  5. Round to 3 significant figures:
    Thus, the value of yy is: y5.87extcmy \approx 5.87 ext{ cm}

Step 2

explain the effect this would have on your answer to part (a).

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Answer

When the diameter of the cone and the diameter of the hemisphere are both increased by the same amount, the radius will also increase. Consequently, the volume of the cone and the hemisphere will both become larger.

Since both volumes contribute to the total volume of T, the total volume will increase as well. This would lead to a higher total volume than the original 120 cm³, requiring a recalculation of the height yy. Therefore, the value of yy would also increase, reflecting the larger sizes and corresponding volumes of the joined solids.

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