A and B are points on a circle with centre O - Edexcel - GCSE Maths - Question 19 - 2019 - Paper 2

Next, we use the information regarding angles on a straight line. Since BOD is a straight line, we can express angle DAB as:

$\angle DAB = \angle ODA + \angle CAD$

Substituting the known values:

$\angle DAB = 32° + 90° = 122°$

Now, we can find angle CAB. The angles in triangle AOB add up to 180°. Thus, we have:

$\angle CAB + \angle DAB + \angle AOB = 180°$

Where angle AOB is equal to angle ODA, as both angles opposite the same segment. So:

$\angle AOB = \angle ODA = 32°$

Now substituting these angles in:

$\angle CAB + 122° + 32° = 180°$

This simplifies to:

$\angle CAB + 154° = 180°$

Hence:

$\angle CAB = 180° - 154° = 26°$