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Here are two rectangles - Edexcel - GCSE Maths - Question 8 - 2019 - Paper 1

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Question 8

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Here are two rectangles. $QR = 10cm$ $BC = PQ$ The perimeter of $ABCD$ is $26cm$ The area of $PQRS$ is $45cm^2$ Find the length of $AB$.

Worked Solution & Example Answer:Here are two rectangles - Edexcel - GCSE Maths - Question 8 - 2019 - Paper 1

Step 1

For $PQ$ to find the length of $PQ$

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Answer

The area of rectangle PQRSPQRS is given by the formula:

extArea=extlengthimesextwidth ext{Area} = ext{length} imes ext{width}
Let the length of PQPQ be xx cm. Since QR=10QR = 10 cm, the area can be set up as:

ximes10=45x imes 10 = 45
Hence, we solve for xx:

x = rac{45}{10} = 4.5 ext{ cm}
Thus, the length of PQPQ is 4.54.5 cm.

Step 2

For the perimeter of $ABCD$ to find the length of $AB$

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Answer

The perimeter of rectangle ABCDABCD is defined as:

extPerimeter=2imes(extlength+extwidth) ext{Perimeter} = 2 imes ( ext{length} + ext{width})
Let the length of ABAB be yy cm. The width BCBC is equal to the length of PQPQ, which is 4.54.5 cm. Therefore, we can set up the equation as:

2(y+4.5)=262(y + 4.5) = 26
Now, simplifying that:

y+4.5=13y + 4.5 = 13
y=134.5y = 13 - 4.5
y=8.5extcmy = 8.5 ext{ cm}
Thus, the length of ABAB is 8.58.5 cm.

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