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At the beginning of 2009, Mr Veale bought a company - Edexcel - GCSE Maths - Question 13 - 2017 - Paper 2

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At the beginning of 2009, Mr Veale bought a company. The value of the company was £50,000 Each year the value of the company increased by 2%. (a) Calculate the val... show full transcript

Worked Solution & Example Answer:At the beginning of 2009, Mr Veale bought a company - Edexcel - GCSE Maths - Question 13 - 2017 - Paper 2

Step 1

Calculate the value of the company at the beginning of 2017

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Answer

To find the value of the company at the beginning of 2017, we need to account for the 2% annual increases over 8 years (from 2009 to 2017).

The formula to calculate the future value considering compound interest is:

FV=PVimes(1+r)nFV = PV imes (1 + r)^n

where:

  • FVFV is the future value.
  • PVPV is the present value (£50,000).
  • rr is the rate of increase (0.02 for 2%).
  • nn is the number of years (8).

Plugging in the values:

FV=50000imes(1+0.02)8FV = 50000 imes (1 + 0.02)^8 FV=50000imes(1.02)850000×1.17165958583.23FV = 50000 imes (1.02)^8 \approx 50000 \times 1.171659 \approx 58583.23

Rounding to the nearest £100, the value of the company at the beginning of 2017 is approximately £58,600.

Step 2

Find the value of x

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Answer

We can use the formula for compound growth to determine the annual percentage increase xx:

For the company starting at £250,000 and increasing to £325,000 over 6 years, we set:

325000=250000imes(1+x100)6325000 = 250000 imes (1 + \frac{x}{100})^6

Dividing both sides by £250,000 gives:

325000250000=(1+x100)6\frac{325000}{250000} = (1 + \frac{x}{100})^6 1.3=(1+x100)61.3 = (1 + \frac{x}{100})^6

To solve for 1+x1001 + \frac{x}{100}, we take the sixth root:

1+x100=1.3161.0451 + \frac{x}{100} = 1.3^{\frac{1}{6}} \approx 1.045

Now, subtracting 1: x1000.045\frac{x}{100} \approx 0.045

Thus, x4.5x \approx 4.5. Therefore, the value of x is approximately 4.5%.

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