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Amanda has two fair 3-sided spinners - Edexcel - GCSE Maths - Question 6 - 2020 - Paper 3

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Amanda has two fair 3-sided spinners. Amanda spins each spinner once. (a) Complete the probability tree diagram. Spinner A lands on 2 Spinner B does not land o... show full transcript

Worked Solution & Example Answer:Amanda has two fair 3-sided spinners - Edexcel - GCSE Maths - Question 6 - 2020 - Paper 3

Step 1

Complete the probability tree diagram.

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Answer

To complete the probability tree diagram, we need to identify the possible outcomes for both spinners.

For each spinner:

  • Spinner A:

    • Probability of landing on 2 = ( \frac{1}{3} )
    • Probability of not landing on 2 = ( \frac{2}{3} )
  • Spinner B:

    • Probability of landing on 2 = ( \frac{1}{3} )
    • Probability of not landing on 2 = ( \frac{2}{3} )

Thus, the completed diagram will have the following branches:

  • Spinner A → lands on 2 (( \frac{1}{3} ))
  • Spinner A → does not land on 2 (( \frac{2}{3} ))

Next, for each outcome of Spinner A, we further branch into Spinner B:

  • If Spinner A lands on 2:

    • Spinner B → lands on 2 (( \frac{1}{3} ))
    • Spinner B → does not land on 2 (( \frac{2}{3} ))
  • If Spinner A does not land on 2:

    • Spinner B → lands on 2 (( \frac{1}{3} ))
    • Spinner B → does not land on 2 (( \frac{2}{3} ))

These probabilities can now be used for part (b).

Step 2

Work out the probability that Spinner A lands on 2 and Spinner B does not land on 2.

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Answer

To find the probability that Spinner A lands on 2 and Spinner B does not land on 2, we use the probabilities from the tree:

  1. The probability of Spinner A landing on 2 is ( \frac{1}{3} ).
  2. The probability of Spinner B not landing on 2 is ( \frac{2}{3} ).

These are independent events, so we multiply the probabilities:

P(A=2 and B2)=P(A=2)×P(B2)=13×23=29P(A = 2 \text{ and } B \neq 2) = P(A = 2) \times P(B \neq 2) = \frac{1}{3} \times \frac{2}{3} = \frac{2}{9}

Thus, the final probability is ( \frac{2}{9} ).

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