Photo AI

Solve the following simultaneous equations: $$x + y = 2$$ $$x - 3y = -2$$ - Edexcel - GCSE Maths - Question 12 - 2022 - Paper 1

Question icon

Question 12

Solve-the-following-simultaneous-equations:--$$x-+-y-=-2$$-$$x---3y-=--2$$-Edexcel-GCSE Maths-Question 12-2022-Paper 1.png

Solve the following simultaneous equations: $$x + y = 2$$ $$x - 3y = -2$$

Worked Solution & Example Answer:Solve the following simultaneous equations: $$x + y = 2$$ $$x - 3y = -2$$ - Edexcel - GCSE Maths - Question 12 - 2022 - Paper 1

Step 1

For a correct method to eliminate either variable or rearrangement of one equation leading to substitution (condone one arithmetic error)

96%

114 rated

Answer

To solve the simultaneous equations, we can first rearrange one of the equations to isolate a variable. Let's take the first equation:

x+y=2x + y = 2

We can rearrange it to get:

x=2yx = 2 - y

Now we can substitute this expression for xx into the second equation.

Step 2

For either correct value of x or correct value of y

99%

104 rated

Answer

Now, substitute x=2yx = 2 - y into the second equation:

x3y=2x - 3y = -2 (2y)3y=2 (2 - y) - 3y = -2

Combining like terms, we have:

24y=22 - 4y = -2

Subtracting 2 from both sides gives:

4y=4-4y = -4

Dividing by -4 yields:

y=1y = 1

Now, substituting y=1y = 1 back into x+y=2x + y = 2:

x+1=2x + 1 = 2

Thus, we find:

x=1x = 1.

Step 3

(a) For a correct substitution of found values into one of the equations as a correct method leading to the second values (condone one arithmetic error)

96%

101 rated

Answer

Finally, substituting x=1x = 1 and y=1y = 1 back into the original equations to verify:

For the first equation: x+y=2x + y = 2 1+1=21 + 1 = 2 (True)

For the second equation: x3y=2x - 3y = -2 13(1)=21 - 3(1) = -2 13=21 - 3 = -2 (True)

Both equations are satisfied, confirming that the solution is correct.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;