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Given the equation: \( y = \frac{1}{\sqrt{2}} \) 1 - Edexcel - GCSE Maths - Question 19 - 2022 - Paper 1

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Given-the-equation:---\(-y-=-\frac{1}{\sqrt{2}}-\)--1-Edexcel-GCSE Maths-Question 19-2022-Paper 1.png

Given the equation: \( y = \frac{1}{\sqrt{2}} \) 1. Find the equation of the line. 2. Solve the quadratic equation. 3. Analyze the solutions of the given quadra... show full transcript

Worked Solution & Example Answer:Given the equation: \( y = \frac{1}{\sqrt{2}} \) 1 - Edexcel - GCSE Maths - Question 19 - 2022 - Paper 1

Step 1

1. Find the equation of the line.

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Answer

To find the equation of the line, we start by noting that our given equation is in the form of a mathematical constant, ( \frac{1}{\sqrt{2}} ). We can express this as:

[ y = \frac{1}{\sqrt{2}} ]

This represents a horizontal line in the Cartesian plane where the value of ( y ) is always ( \frac{1}{\sqrt{2}} ).

Step 2

2. Solve the quadratic equation.

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Answer

Assuming that we want to solve for ( ax^2 + bx + c = 0 ) where we can rewrite it as follows:

[ ax^2 + bx + c = 0 ]

We can use the quadratic formula:

[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]

This formula allows us to find the roots of the equation based on the coefficients ( a, b, \text{ and } c ).

Step 3

3. Analyze the solutions of the given quadratic in real numbers.

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The analysis of the solutions can be carried out by determining the discriminant ( D = b^2 - 4ac ). If ( D > 0 ), we have two distinct real solutions. If ( D = 0 ), there is exactly one real solution, and if ( D < 0 ), there are no real solutions. This provides a comprehensive way to analyze the nature of the roots in the context of real numbers.

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