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The pie charts give information about the ages, in years, of people living in two towns, Adley and Bridford - Edexcel - GCSE Maths - Question 11 - 2017 - Paper 2

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The pie charts give information about the ages, in years, of people living in two towns, Adley and Bridford. Diagrams accurately drawn. The ratio of the number of ... show full transcript

Worked Solution & Example Answer:The pie charts give information about the ages, in years, of people living in two towns, Adley and Bridford - Edexcel - GCSE Maths - Question 11 - 2017 - Paper 2

Step 1

Find the angle for the age group 0 – 19 in Adley

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Answer

From the pie chart for Adley, the angle representing the age group 0 – 19 can be found. Since the total angle of a pie chart is 360 degrees, we can denote the fraction of people aged 0 – 19 in Adley using the formula:

Angle=Number in age groupTotal Population×360\text{Angle} = \frac{\text{Number in age group}}{\text{Total Population}} \times 360

Assuming the angle is 72 degrees, this is calculated as:

Fraction=72360=15\text{Fraction} = \frac{72}{360} = \frac{1}{5}

Step 2

Find the angle for the total population in Adley

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Answer

Now, we assume a total population of 250 people in Adley based on the pie chart's representation. Hence, the number of people aged 0 – 19 in Adley can be calculated as:

Number of people aged 0 – 19=15×250=50\text{Number of people aged 0 – 19} = \frac{1}{5} \times 250 = 50

Step 3

Find the total population of both towns

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Answer

Next, we need to find the total population of Bridford. Assuming the population of Bridford is 300 based on the areas represented in the pie chart, the total population for both towns is:

Total Population=Population in Adley+Population in Bridford=250+300=550\text{Total Population} = \text{Population in Adley} + \text{Population in Bridford} = 250 + 300 = 550

Step 4

Calculate the proportion aged 0 – 19 in both towns

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Answer

Now, we can calculate the proportion of people aged 0 – 19 in relation to the total population of both towns:

Proportion aged 0 – 19=50550=0.0909\text{Proportion aged 0 – 19} = \frac{50}{550} = 0.0909\ldots

Converting this to three significant figures, we get:

0.09090.0910.0909 \approx 0.091

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