16. $p = \frac{2e}{\sqrt{f}}$ $e = 6.8$ correct to 1 decimal place - Edexcel - GCSE Maths - Question 17 - 2022 - Paper 3

The value of f is given as 0.05 correct to 1 significant figure. Thus, the upper bound is:

Upper bound of f = 0.05 + 0.005 = 0.055

Now we can substitute the upper bounds into the formula to find p:

$p = \frac{2 \times 6.85}{\sqrt{0.055}}$

Calculating $\sqrt{0.055}$:

$\sqrt{0.055} \approx 0.2344$

Substituting that back into the formula gives:

$p = \frac{2 \times 6.85}{0.2344} \approx 58.5$

The final answer for $p$, rounded to 3 significant figures, is:

$p \approx 58.5$