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PQR and QRS are triangles - Edexcel - GCSE Maths - Question 19 - 2022 - Paper 2

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PQR and QRS are triangles. Calculate the length of QS. Give your answer correct to 3 significant figures. You must show all your working. (11 cm, 27°, 9.4 cm, 88°,... show full transcript

Worked Solution & Example Answer:PQR and QRS are triangles - Edexcel - GCSE Maths - Question 19 - 2022 - Paper 2

Step 1

Calculate the length of QR using the sine rule

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Answer

We can use the sine rule to find the length of QR. According to the sine rule:

PQsin(R)=QRsin(P)\frac{PQ}{\sin(R)} = \frac{QR}{\sin(P)}

Substituting the known values:

11sin(88)=QRsin(27)\frac{11}{\sin(88^{\circ})} = \frac{QR}{\sin(27^{\circ})}

Calculating the right side:

  1. Calculate (\sin(88^{\circ}) \approx 0.998)
  2. Calculate (\sin(27^{\circ}) \approx 0.454)

Now rearranging the equation:

QR=11sin(27)sin(88)QR = \frac{11 \cdot \sin(27^{\circ})}{\sin(88^{\circ})}

Substituting:

QR110.4540.9985.01 cmQR \approx \frac{11 \cdot 0.454}{0.998} \approx 5.01 \text{ cm}

Step 2

Calculate the length of QS using the sine rule

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Answer

Now we can use the sine rule again to calculate QS:

QRsin(S)=QSsin(Q)\frac{QR}{\sin(S)} = \frac{QS}{\sin(Q)}

Where (S=41^{\circ}) and (Q=88^{\circ})

Substituting the known values:

5.01sin(41)=QSsin(88)\frac{5.01}{\sin(41^{\circ})} = \frac{QS}{\sin(88^{\circ})}

Calculating the right side:

  1. Calculate (\sin(41^{\circ}) \approx 0.656)

Rearranging gives:

QS=5.01sin(88)sin(41)QS = \frac{5.01 \cdot \sin(88^{\circ})}{\sin(41^{\circ})}

Substituting:

QS5.010.9980.6567.63 cmQS \approx \frac{5.01 \cdot 0.998}{0.656} \approx 7.63 \text{ cm}

Rounding to 3 significant figures, the answer is 7.63 cm.

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