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A, B and C are points on a circle of radius 5 cm, centre O - Edexcel - GCSE Maths - Question 18 - 2017 - Paper 3

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A, B and C are points on a circle of radius 5 cm, centre O. DA and DC are tangents to the circle. DO = 9 cm Work out the length of arc ABC. Give your answer correct... show full transcript

Worked Solution & Example Answer:A, B and C are points on a circle of radius 5 cm, centre O - Edexcel - GCSE Maths - Question 18 - 2017 - Paper 3

Step 1

Recognize that angle DAB is a right angle

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Answer

Since DA and DC are tangents to the circle at points A and C respectively, the angles DAB and DCA are both right angles (90°). Therefore, triangle OAD is a right triangle.

Step 2

Set up an equation using trigonometry for triangle OAD

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Answer

Using the cosine rule, we know that:

extCos(DOA)=OADO ext{Cos}(DOA) = \frac{OA}{DO}

Given that OA (the radius) is 5 cm and DO is 9 cm, we write:

extCos(DOA)=59 ext{Cos}(DOA) = \frac{5}{9}

Step 3

Find the angle DOA

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Answer

Using the inverse cosine, we can find the angle:

DOA=Cos1(59)54.74°DOA = \text{Cos}^{-1}\left(\frac{5}{9}\right) \approx 54.74°

Step 4

Calculate the length of arc ABC

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Answer

To find the length of arc ABC, we first determine the angle AOC, which is double the angle DOA:

AOC=2×DOA2×54.74°109.48°AOC = 2 \times DOA \approx 2 \times 54.74° \approx 109.48°

Next, convert this angle into radians:

AOCrad=109.48180×π1.913 radAOC_{rad} = \frac{109.48}{180} \times \pi \approx 1.913 \text{ rad}

Finally, the length of arc ABC can be calculated as:

Length=r×θ=5×1.9139.565extcm\text{Length} = r \times \theta = 5 \times 1.913 \approx 9.565 ext{ cm}

Step 5

Round the length to 3 significant figures

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Answer

Rounding 9.565 cm to 3 significant figures gives us:

9.57 cm

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