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In a bag there are only red counters, blue counters, green counters and pink counters - Edexcel - GCSE Maths - Question 7 - 2021 - Paper 3

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In a bag there are only red counters, blue counters, green counters and pink counters. A counter is going to be taken at random from the bag. The table shows the pr... show full transcript

Worked Solution & Example Answer:In a bag there are only red counters, blue counters, green counters and pink counters - Edexcel - GCSE Maths - Question 7 - 2021 - Paper 3

Step 1

Complete the table.

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Answer

To complete the table, we first denote the probability of taking a green counter as P(g)P(g) and the probability of taking a pink counter as P(p)P(p).

From the information given, we know:

  1. P(g)=P(p)+0.2P(g) = P(p) + 0.2.
  2. The sum of all probabilities should equal 1: P(r)+P(b)+P(g)+P(p)=1P(r) + P(b) + P(g) + P(p) = 1 Where:
    • P(r)=0.05P(r) = 0.05 (red)
    • P(b)=0.15P(b) = 0.15 (blue)
    • Thus, 0.05+0.15+P(g)+P(p)=10.05 + 0.15 + P(g) + P(p) = 1 P(g)+P(p)=0.8P(g) + P(p) = 0.8

Substituting P(g)P(g): P(p)+0.2+P(p)=0.8P(p) + 0.2 + P(p) = 0.8 2P(p)+0.2=0.82P(p) + 0.2 = 0.8 2P(p)=0.80.2=0.62P(p) = 0.8 - 0.2 = 0.6 P(p)=0.3P(p) = 0.3

Thus, substituting back, we find: P(g)=0.3+0.2=0.5P(g) = 0.3 + 0.2 = 0.5

The completed table is:

Colourredbluegreenpink
Probability0.050.150.50.3

Step 2

Work out the total number of counters in the bag.

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Answer

Let the total number of counters in the bag be denoted by xx.

Given that there are 18 blue counters, and from the completed table above:

  • The probability of taking a blue counter is P(b)=0.15P(b) = 0.15.

Using the probability relation: P(b)=number of blue countersx0.15=18xP(b) = \frac{\text{number of blue counters}}{x} \Rightarrow 0.15 = \frac{18}{x}

To find xx, rearranging gives: x=180.15x=120.x = \frac{18}{0.15} \Rightarrow x = 120.

Therefore, the total number of counters in the bag is 120.

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