Work out
\[
\frac{2.5 \times \sin{43^{\circ}}}{\sqrt{8.2^2 - 0.5}}
\]
Give your answer correct to 3 significant figures. - Edexcel - GCSE Maths - Question 7 - 2019 - Paper 3
Question 7
Work out
\[
\frac{2.5 \times \sin{43^{\circ}}}{\sqrt{8.2^2 - 0.5}}
\]
Give your answer correct to 3 significant figures.
Worked Solution & Example Answer:Work out
\[
\frac{2.5 \times \sin{43^{\circ}}}{\sqrt{8.2^2 - 0.5}}
\]
Give your answer correct to 3 significant figures. - Edexcel - GCSE Maths - Question 7 - 2019 - Paper 3
Step 1
Calculate the numerator: 2.5 × sin(43°)
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Answer
First, we calculate the sine of 43 degrees:
[
sin(43^{\circ}) \approx 0.68199
]
Now, we will multiply by 2.5:
[
2.5 \times 0.68199 \approx 1.704975
]
Step 2
Calculate the denominator: \sqrt{8.2^2 - 0.5}
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Answer
First, calculate (8.2^2):
[
8.2^2 = 67.24
]
Next, subtract 0.5:
[
67.24 - 0.5 = 66.74
]
Now take the square root:
[
\sqrt{66.74} \approx 8.166
]
Step 3
Combine the numerator and denominator
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Answer
Now divide the results from the previous steps:
[
\frac{1.704975}{8.166} \approx 0.20849
]
Step 4
Round to 3 significant figures
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Answer
The final step is to round 0.20849 to 3 significant figures:
[
0.208 ext{ (rounded to 3 significant figures)}
]
![Work-out-\[-\frac{2.5-\times-\sin{43^{\circ}}}{\sqrt{8.2^2---0.5}}-\]-Give-your-answer-correct-to-3-significant-figures.-Edexcel-GCSE Maths-Question 7-2019-Paper 3.png](https://cdn.simplestudy.io/assets/backend/uploads/question/GCSE_Maths_Edexcel_QP_7_JP3_2019.jpg)
