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CDEF is a quadrilateral - Edexcel - GCSE Maths - Question 24 - 2022 - Paper 3

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CDEF is a quadrilateral. $ ext{FE} = a ext{ and } ext{ED} = b ext{ and } ext{CD} = 2a$ The point P is such that $ ext{CEF}$ is a straight line and that $ ext{C... show full transcript

Worked Solution & Example Answer:CDEF is a quadrilateral - Edexcel - GCSE Maths - Question 24 - 2022 - Paper 3

Step 1

CE = EP

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Answer

Given that extCE=extEP ext{CE} = ext{EP} and extFE=a ext{FE} = a, we can represent the points in vector form.

Let extC=extO ext{C} = ext{O} (the origin). Thus,

  • extE=aextinthedirectionofextCE ext{E} = a ext{ in the direction of } ext{CE},
  • extF=extE+a=a+a=2a ext{F} = ext{E} + a = a + a = 2a.

This allows us to express the vectors:

  • extCF=extFextC=2a0=2a ext{CF} = ext{F} - ext{C} = 2a - 0 = 2a,
  • extDP=extPextD=extE+b(2a)=2a+b2a=b ext{DP} = ext{P} - ext{D} = ext{E} + b - (2a) = 2a + b - 2a = b.

Step 2

CF and DP

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Answer

extCF=2a ext{CF} = 2a and extDP=b ext{DP} = b. Using the fact that extCFextandextDP ext{CF} ext{ and } ext{DP} are both directed along the same line, we conclude that the vectors are proportional. Hence, extCF ext{CF} is parallel to extDP ext{DP}.$

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