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Write down the coordinates of the turning point on the graph of $y = (x + 12)^2 - 7$. - Edexcel - GCSE Maths - Question 18 - 2020 - Paper 2

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Write-down-the-coordinates-of-the-turning-point-on-the-graph-of-$y-=-(x-+-12)^2---7$.-Edexcel-GCSE Maths-Question 18-2020-Paper 2.png

Write down the coordinates of the turning point on the graph of $y = (x + 12)^2 - 7$.

Worked Solution & Example Answer:Write down the coordinates of the turning point on the graph of $y = (x + 12)^2 - 7$. - Edexcel - GCSE Maths - Question 18 - 2020 - Paper 2

Step 1

Identify the quadratic function

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Answer

We have the equation of the graph as:

y=(x+12)27y = (x + 12)^2 - 7

This is in the vertex form of a quadratic function, which is given by: y=a(xh)2+ky = a(x - h)^2 + k where (h,k)(h, k) represents the turning point.

Step 2

Determine the turning point

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Answer

In our equation,

  • The value of hh is 12-12 (from x+12x + 12, we get x(12)x - (-12))
  • The value of kk is 7-7.

Therefore, the turning point is at the coordinates: (12,7)(-12, -7).

Step 3

Write down the coordinates

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Answer

The coordinates of the turning point on the graph are:

(12,7)(-12, -7)

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