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The diagram shows a hexagon - Edexcel - GCSE Maths - Question 6 - 2019 - Paper 3

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The diagram shows a hexagon. The hexagon has one line of symmetry. $AF = BC$ $EF = CD$ Angle $ABC = 117^{ ext{o}}$ Angle $BCD = 2 \times angle \; CDE$ Work out th... show full transcript

Worked Solution & Example Answer:The diagram shows a hexagon - Edexcel - GCSE Maths - Question 6 - 2019 - Paper 3

Step 1

Find the sum of the interior angles of a hexagon

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Answer

The formula for the sum of the interior angles of a polygon with ( n ) sides is given by: Sum=(n2)×180\text{Sum} = (n - 2) \times 180^{\circ} For a hexagon, where ( n = 6 ): Sum=(62)×180=4×180=720\text{Sum} = (6 - 2) \times 180^{\circ} = 4 \times 180^{\circ} = 720^{\circ}

Step 2

Determine the angles in the hexagon

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Answer

Since the hexagon has one line of symmetry, the opposite angles are equal. Let:

  • Angle ( AFE = x )
  • Then angle ( BCD = 2 \times angle , CDE )
  • The interior angles of the hexagon become: x+117+2y+y+y+y=720x + 117^{\circ} + 2y + y + y + y = 720^{\circ} Where ( y ) is the angle ( CDE ). This simplifies to: x+117+5y=720(1)x + 117^{\circ} + 5y = 720^{\circ} \quad (1)

Step 3

Establish the relationships between the angles

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Answer

From the properties of angles: Since angle ( BCD = 2y ): So, BCD+CDE=3y=117y=39BCD + CDE = 3y = 117^{\circ} \to y = 39^{\circ}. Substituting ( y ) in (1): x+117+5(39)=720x + 117^{\circ} + 5(39^{\circ}) = 720^{\circ} This gives: x+117+195=720x + 117^{\circ} + 195^{\circ} = 720^{\circ}

Step 4

Calculate the value of angle AFE

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Answer

Thus, x+312=720x + 312^{\circ} = 720^{\circ} Now, isolating ( x ): x=720312=408x = 720^{\circ} - 312^{\circ} = 408^{\circ}. To find the angle ( AFE ): AFE=408360=48.AFE = 408^{\circ} - 360^{\circ} = 48^{\circ}.

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