Photo AI

10 (a) Solve \( \frac{9 + x}{7} = 11 - x \) \( x = \) (b) Simplify \( \frac{4(y + 3)^3}{(y + 3)^2} \) \( = \) - Edexcel - GCSE Maths - Question 13 - 2019 - Paper 3

Question icon

Question 13

10-(a)-Solve-\(-\frac{9-+-x}{7}-=-11---x-\)---\(-x-=-\)----(b)-Simplify-\(-\frac{4(y-+-3)^3}{(y-+-3)^2}-\)---\(-=-\)-Edexcel-GCSE Maths-Question 13-2019-Paper 3.png

10 (a) Solve \( \frac{9 + x}{7} = 11 - x \) \( x = \) (b) Simplify \( \frac{4(y + 3)^3}{(y + 3)^2} \) \( = \)

Worked Solution & Example Answer:10 (a) Solve \( \frac{9 + x}{7} = 11 - x \) \( x = \) (b) Simplify \( \frac{4(y + 3)^3}{(y + 3)^2} \) \( = \) - Edexcel - GCSE Maths - Question 13 - 2019 - Paper 3

Step 1

Solve \( \frac{9 + x}{7} = 11 - x \)

96%

114 rated

Answer

To solve the equation, we first eliminate the fraction by multiplying both sides by 7:

9+x=7(11−x)9 + x = 7(11 - x)

Expanding the right side gives:

9+x=77−7x9 + x = 77 - 7x

Next, we isolate all terms containing ( x ) on one side of the equation. Adding ( 7x ) to both sides results in:

9+x+7x=779 + x + 7x = 77

Simplifying this, we have:

9+8x=779 + 8x = 77

Now we subtract 9 from both sides:

8x=77−98x = 77 - 9

Thus:

8x=688x = 68

Dividing by 8 gives:

x=688=8.5x = \frac{68}{8} = 8.5

Step 2

Simplify \( \frac{4(y + 3)^3}{(y + 3)^2} \)

99%

104 rated

Answer

To simplify the expression, we can divide the two terms. Since the numerator and the denominator share a common factor of ( (y + 3)^2 ), we can reduce it:

4(y+3)3(y+3)2=4(y+3)3−2=4(y+3)1=4(y+3)\frac{4(y + 3)^3}{(y + 3)^2} = 4(y + 3)^{3-2} = 4(y + 3)^1 = 4(y + 3)

Therefore, the simplified expression is:

4(y+3)4(y + 3)

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;