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2 (a) A cyclist has a mass of 64 kg - Edexcel - GCSE Physics Combined Science - Question 2 - 2021 - Paper 1

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2 (a) A cyclist has a mass of 64 kg. (i) The cyclist rides from a flat road to the top of a hill. The top of the hill is 24 m above the flat road. Calculate the gai... show full transcript

Worked Solution & Example Answer:2 (a) A cyclist has a mass of 64 kg - Edexcel - GCSE Physics Combined Science - Question 2 - 2021 - Paper 1

Step 1

(i) Calculate the gain in gravitational potential energy, ΔGPE, of the cyclist.

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Answer

To calculate the gain in gravitational potential energy, we use the formula:

riangleGPE=mimesgimesriangleh riangle GPE = m imes g imes riangle h

Substituting the given values:

  • Mass (m) = 64 kg
  • Gravitational acceleration (g) = 10 N/kg
  • Height change (Δh) = 24 m

So, we have:

riangleGPE=64imes10imes24 riangle GPE = 64 imes 10 imes 24

Calculating this gives:

riangleGPE=15360extJ riangle GPE = 15360 ext{ J}

Thus, the gain in gravitational potential energy is 15360 J.

Step 2

(ii) Calculate the kinetic energy of the cyclist when the cyclist is travelling at 6.0 m/s.

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Answer

To find the kinetic energy (KE), we use the equation:

KE = rac{1}{2} imes m imes v^2

Substituting the given values:

  • Mass (m) = 64 kg
  • Velocity (v) = 6.0 m/s

The calculation becomes:

KE = rac{1}{2} imes 64 imes (6.0)^2

Calculating the velocity squared:

(6.0)2=36(6.0)^2 = 36

Now substituting back:

KE = rac{1}{2} imes 64 imes 36

Calculating this gives:

KE=32imes36=1152extJKE = 32 imes 36 = 1152 ext{ J}

Thus, the kinetic energy is 1152 J.

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