Figure 1 shows a lamp connected to a d.c. power supply. The power supply provides a potential difference (voltage) of 4.5V. The current in the lamp is 0.30 A. (i) Calculate the resistance of the lamp. Use the equation R = \frac{V}{I} (1) (ii) Calculate the power supplied to the lamp. (2)

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Figure 1 shows a lamp connected to a d.c - Edexcel - GCSE Physics Combined Science - Question 1 - 2022 - Paper 1

Question 1

Figure 1 shows a lamp connected to a d.c. power supply. The power supply provides a potential difference (voltage) of 4.5V. The current in the lamp is 0.30 A. (i) ... show full transcript

Worked Solution & Example Answer:Figure 1 shows a lamp connected to a d.c - Edexcel - GCSE Physics Combined Science - Question 1 - 2022 - Paper 1

Step 1

(i) Calculate the resistance of the lamp.

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Answer

To calculate the resistance of the lamp, we use the formula:

$R = \frac{V}{I}$

Where:

V = 4.5 V (voltage across the lamp)
I = 0.30 A (current through the lamp)

Substituting the values into the equation:

$R = \frac{4.5}{0.30} = 15 \ \Omega$

Thus, the resistance of the lamp is 15 Ω.

Step 2

(ii) Calculate the power supplied to the lamp.

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Answer

To find the power supplied to the lamp, we use the formula:

$P = V \times I$

Again, substituting the known values:

V = 4.5 V
I = 0.30 A

Thus, the power can be calculated as follows:

$P = 4.5 \times 0.30 = 1.35 \ W$

Therefore, the power supplied to the lamp is approximately 1.4 W.

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