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A student measures the density of glass - Edexcel - GCSE Physics Combined Science - Question 4 - 2019 - Paper 1

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A student measures the density of glass. The student has - a bag of marbles, all made from the same type of glass - a weighing balance - a plastic measuring cylinde... show full transcript

Worked Solution & Example Answer:A student measures the density of glass - Edexcel - GCSE Physics Combined Science - Question 4 - 2019 - Paper 1

Step 1

Describe how the student could find, as accurately as possible, the density of the glass used for the marbles.

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Answer

  1. Find the Mass of the Marbles:

    • Use the weighing balance to measure the mass of the bag of marbles.
  2. Measure the Volume of Water Displaced:

    • Fill the measuring cylinder with a known volume of water and record this level.
    • Carefully add the marbles into the cylinder, ensuring they are fully submerged.
    • Measure the new water level and calculate the change in level to find the volume of water displaced by the marbles.
  3. Calculate the Volume Displaced:

    • The volume of the displaced water equals the volume of the marbles.
  4. Calculate the Density:

    • Use the formula for density: Density=MassVolume\text{Density} = \frac{\text{Mass}}{\text{Volume}}
    • Substitute the mass of the marbles and the volume of water displaced into this equation.
    • Optionally, use several marbles to improve measurement accuracy and take an average for the density calculation.

Step 2

(i) Calculate the temperature of the water before it was heated.

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Answer

  1. Identify the Given Values:

    • Mass (m) = 0.25 kg
    • Specific heat capacity (c) = 4200 J/kg°C
    • Thermal energy supplied (Q) = 84,000 J
  2. Use the Heat Energy Formula:

    • The formula is: Q=m×c×ΔθQ = m \times c \times \Delta \theta where (\Delta \theta) is the change in temperature.
  3. Substitute the Values:

    • Substitute into the formula: 84,000=0.25×4200×Δθ84,000 = 0.25 \times 4200 \times \Delta \theta
  4. Rearrange to Find (\Delta \theta$$:

    • Rearranging gives: Δθ=84,0000.25×4200\Delta \theta = \frac{84,000}{0.25 \times 4200}
    • Calculate (\Delta \theta = 80°C$$.
  5. Determine the Initial Temperature:

    • Since the boiling point is 100°C, the temperature before heating is: Temperature before heating=100°C80°C=20°C\text{Temperature before heating} = 100°C - 80°C = 20°C.

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