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Question 5
Rutherford devised an experiment to fire alpha particles at thin gold foil. It was found that alpha particles were scattered by the gold foil. The gold foil was 4.0 ... show full transcript
Step 1
Answer
To determine how many gold atoms fit across the thickness of the gold foil, we can start by calculating the thickness of the foil in nanometers:
Convert the thickness from meters to nanometers:
.
Calculate how many gold atoms fit into the thickness:
= rac{4.0 imes 10^{2} ext{ nm}}{0.15 ext{ nm}} = rac{400}{0.15} ext{ atoms} \ \ ext{Number of atoms} \ = 2666.67 \ \ \ = 2700 \text{ (rounded)}.$
Step 2
Answer
From the graph in Figure 7:
Estimate the number of particles scattered through 5°. Based on the graph, it appears to be around .
Estimate the number of particles scattered through 100°. From the graph, it appears this value is about .
Thus the ratio is:
= \frac{10^{6}}{10^{2}} = 10^{4} \ \text{Ratio} = 10,000.
Step 3
Answer
The scattering of alpha particles at different angles provides crucial insights into the structure of the atom:
Step 4
Answer
To model the scattering of alpha particles using the apparatus:
Step 5
Answer
One limitation of this model is that it does not accurately represent the scale and interaction forces of real alpha particles and gold atoms. Unlike the solid marble, alpha particles are much smaller and can interact differently with the atomic structure, including repulsion and other quantum effects that are not captured in this physical model.
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