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Figure 2 shows an energy transfer diagram for a steam engine - Edexcel - GCSE Physics: Combined Science - Question 2 - 2019 - Paper 1

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Figure 2 shows an energy transfer diagram for a steam engine. The diagram shows the amounts of energy transferred each second by the steam engine. energy input 200... show full transcript

Worked Solution & Example Answer:Figure 2 shows an energy transfer diagram for a steam engine - Edexcel - GCSE Physics: Combined Science - Question 2 - 2019 - Paper 1

Step 1

Calculate the amount of wasted energy.

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Answer

To find the wasted energy, we subtract the useful energy output from the total energy input:

wasted energy=energy inputuseful energy output=2000 J160 J=1840 J\text{wasted energy} = \text{energy input} - \text{useful energy output} = 2000 \text{ J} - 160 \text{ J} = 1840 \text{ J}

Step 2

Calculate the efficiency of the steam engine.

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Answer

Using the given formula for efficiency:

efficiency=useful energy transferred by the steam enginetotal energy supplied to the steam engine\text{efficiency} = \frac{\text{useful energy transferred by the steam engine}}{\text{total energy supplied to the steam engine}}

Substituting the values:

efficiency=160 J2000 J=0.08\text{efficiency} = \frac{160 \text{ J}}{2000 \text{ J}} = 0.08

Multiplying by 100 to convert to percentage:

efficiency=0.08×100=8%\text{efficiency} = 0.08 \times 100 = 8\%

Step 3

State what happens to the wasted energy.

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Answer

The wasted energy is typically lost to the surroundings as heat. This loss decreases the overall energy efficiency of the steam engine.

Step 4

State two ways that the use of coal might be harmful to the environment.

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Answer

  1. Burning coal releases greenhouse gases, contributing to climate change.
  2. Coal mining can cause environmental degradation, including habitat destruction and water pollution.

Step 5

Calculate the kinetic energy of the model train.

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Answer

The formula for kinetic energy is:

kinetic energy=12×mass×(speed)2\text{kinetic energy} = \frac{1}{2} \times \text{mass} \times \text{(speed)}^2

Substituting the values:

kinetic energy=12×8.0 kg×(1.5 m/s)2=12×8.0 kg×2.25 m2/s2=9.0 J\text{kinetic energy} = \frac{1}{2} \times 8.0 \text{ kg} \times (1.5 \text{ m/s})^2 = \frac{1}{2} \times 8.0 \text{ kg} \times 2.25 \text{ m}^2/\text{s}^2 = 9.0 \text{ J}

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