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3 This question is about using the mains electricity supply - Edexcel - GCSE Physics Combined Science - Question 3 - 2021 - Paper 1

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3 This question is about using the mains electricity supply. (a) (i) An electric kettle is used to boil some water. The mains supply voltage is 230 V. The power sup... show full transcript

Worked Solution & Example Answer:3 This question is about using the mains electricity supply - Edexcel - GCSE Physics Combined Science - Question 3 - 2021 - Paper 1

Step 1

Calculate the current in the kettle.

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Answer

To find the current supplied to the kettle, we will use the formula:

I=PVI = \frac{P}{V}

Where:

  • P=1.9 kW=1900 WP = 1.9 \text{ kW} = 1900 \text{ W}
  • V=230 VV = 230 \text{ V}

Substituting the values in, we have:

I=19002308.26 AI = \frac{1900}{230} \approx 8.26 \text{ A}

Thus, the current supplied to the kettle is approximately 8.26 A.

Step 2

Calculate the energy transferred to the coffee machine in 120 s.

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Answer

To calculate the energy transferred, we use the formula:

E=V×I×tE = V \times I \times t

Where:

  • V=230 VV = 230 \text{ V}
  • I=7.4 AI = 7.4 \text{ A}
  • t=120 st = 120 \text{ s}

Substituting the values in, we find:

E=230×7.4×120=2,032,800 JE = 230 \times 7.4 \times 120 = 2,032,800 \text{ J}

Therefore, the energy transferred to the coffee machine is 2,032,800 J.

Step 3

State the name of wire X and the name of wire Y.

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Answer

Wire X is earth and wire Y is live.

Step 4

State the name of component Z.

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Answer

Component Z is a fuse.

Step 5

Calculate the input current to the transformer.

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Answer

To find the input current, we rearrange the equation:

inputcurrent×inputvoltage=outputcurrent×outputvoltageinput \, current \times input \, voltage = output \, current \times output \, voltage

So we rearrange to:

inputcurrent=outputcurrent×outputvoltageinputvoltageinput \, current = \frac{output \, current \times output \, voltage}{input \, voltage}

Substituting the values:

inputcurrent=2.37×1902300.196 Ainput \, current = \frac{2.37 \times 190}{230} \approx 0.196 \text{ A}

Thus, the input current to the transformer is approximately 0.196 A.

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