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This question is about energy changes - Edexcel - GCSE Physics Combined Science - Question 4 - 2021 - Paper 1

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This question is about energy changes. (a) Figure 8 shows a water slide. A person travels from the top to the bottom of the water slide. (i) The mass of the person... show full transcript

Worked Solution & Example Answer:This question is about energy changes - Edexcel - GCSE Physics Combined Science - Question 4 - 2021 - Paper 1

Step 1

Calculate the change in gravitational potential energy for the person.

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Answer

To find the change in gravitational potential energy (GPE), we can use the formula:

ΔGPE=m×g×h\Delta GPE = m \times g \times h

Substituting the given values:

  • Mass, m = 72 kg
  • Gravitational field strength, g = 10 N/kg
  • Change in height, h = 7.0 m

Calculating:

ΔGPE=72×10×7.0=5040 J\Delta GPE = 72 \times 10 \times 7.0 = 5040 \text{ J}

Thus, the change in gravitational potential energy is 5040 J.

Step 2

Explain what happens to the energy as the person comes to rest after the end of the water slide.

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Answer

As the person comes to rest after the end of the water slide, the gravitational potential energy that was converted into kinetic energy during the slide is dissipated. This energy is transferred to the surroundings, primarily through friction with the slide and air resistance. Some energy may also be transformed into thermal energy due to the friction between the person's body and the slide, leading to a slight rise in temperature.

Step 3

Explain which one of the three distances shown in Figure 9 should be used to calculate the work done against the force of friction between the box and the slope.

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Answer

To calculate the work done against the force of friction between the box and the slope, the distance moved in the direction of the frictional force should be considered. In Figure 9, this is represented by the length of the slope (hypotenuse), which allows us to account for the work done against friction as the box moves upwards along the slope.

Step 4

Calculate the kinetic energy of a tennis ball travelling at 28 m/s.

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Answer

To calculate the kinetic energy (KE) of the tennis ball, we use the equation:

KE=12×m×v2KE = \frac{1}{2} \times m \times v^2

Where:

  • Mass, m = 58 g = 0.058 kg (converted to kg)
  • Velocity, v = 28 m/s

Substituting the values:

KE=12×0.058×(28)2KE = \frac{1}{2} \times 0.058 \times (28)^2

Calculating:

KE=12×0.058×784=22.736 JKE = \frac{1}{2} \times 0.058 \times 784 = 22.736 \text{ J}

Therefore, the kinetic energy of the tennis ball is approximately 23 J.

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