1. Which of these is the equation for work done?
A work done = force ÷ distance moved in direction of force
B work done = force × distance moved in direction of force
C work done = force × distance moved at right angles to direction of force
D work done = force × distance moved at right angles to direction of force
(b) A ball has a mass of 0.046 kg - Edexcel - GCSE Physics Combined Science - Question 1 - 2019 - Paper 1
Question 1
1. Which of these is the equation for work done?
A work done = force ÷ distance moved in direction of force
B work done = force × distance moved in dir... show full transcript
Worked Solution & Example Answer:1. Which of these is the equation for work done?
A work done = force ÷ distance moved in direction of force
B work done = force × distance moved in direction of force
C work done = force × distance moved at right angles to direction of force
D work done = force × distance moved at right angles to direction of force
(b) A ball has a mass of 0.046 kg - Edexcel - GCSE Physics Combined Science - Question 1 - 2019 - Paper 1
Step 1
Which of these is the equation for work done?
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Answer
The correct answer is B: work done = force × distance moved in direction of force. This equation reflects that work is calculated by the product of the force applied and the distance over which that force is applied in its direction.
Step 2
Calculate the change in gravitational potential energy when the ball is lifted through a vertical height of 2.05 m.
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Answer
To find the change in gravitational potential energy (ΔGPE), we use the formula:
ΔGPE=m×g×Δh
Where:
m = mass of the ball = 0.046 kg
g = acceleration due to gravity ≈ 9.81 m/s²
Δh = height lifted = 2.05 m
Substituting the values:
ΔGPE=0.046imes9.81imes2.05
Calculating this gives:
ΔGPEext≈0.932extJ
Thus, the change in gravitational potential energy is approximately 0.932 J.
Step 3
Calculate the kinetic energy of the ball when the speed of the ball is 3.5 m/s.
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Answer
The formula for kinetic energy (KE) is:
KE=21mv2
Where:
m = mass of the ball = 0.046 kg
v = speed of the ball = 3.5 m/s
Now substituting the values:
KE=21×0.046×(3.5)2
Calculating this gives:
KE≈21×0.046×12.25=0.28extJ
Therefore, the kinetic energy of the ball when it is moving at 3.5 m/s is approximately 0.28 J.