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(a) Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in direction of force C work done = force ÷ distance moved at right angles to direction of force D work done = force × distance moved at right angles to direction of force (b) A ball has a mass of 0.046 kg - Edexcel - GCSE Physics: Combined Science - Question 5 - 2019 - Paper 1

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(a)-Which-of-these-is-the-equation-for-work-done?---A--work-done-=-force-÷-distance-moved-in-direction-of-force---B--work-done-=-force-×-distance-moved-in-direction-of-force---C--work-done-=-force-÷-distance-moved-at-right-angles-to-direction-of-force---D--work-done-=-force-×-distance-moved-at-right-angles-to-direction-of-force---(b)-A-ball-has-a-mass-of-0.046-kg-Edexcel-GCSE Physics: Combined Science-Question 5-2019-Paper 1.png

(a) Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in direction ... show full transcript

Worked Solution & Example Answer:(a) Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in direction of force C work done = force ÷ distance moved at right angles to direction of force D work done = force × distance moved at right angles to direction of force (b) A ball has a mass of 0.046 kg - Edexcel - GCSE Physics: Combined Science - Question 5 - 2019 - Paper 1

Step 1

Which of these is the equation for work done?

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Answer

The correct answer is B: work done = force × distance moved in direction of force.

Step 2

Calculate the change in gravitational potential energy when the ball is lifted through a vertical height of 2.05 m.

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Answer

Using the equation

ΔGPE=m×g×ΔhΔGPE = m × g × Δh

where:

  • m = 0.046 kg
  • g = 9.81 m/s²
  • Δh = 2.05 m

Therefore,

ΔGPE=0.046imes9.81imes2.05=0.92extJΔGPE = 0.046 imes 9.81 imes 2.05 = 0.92 ext{ J}

Step 3

Calculate the kinetic energy of the ball when the speed of the ball is 3.5 m/s.

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Answer

The kinetic energy (KE) can be calculated using the formula:

KE = rac{1}{2}mv^2

Substituting the values:

  • m = 0.046 kg
  • v = 3.5 m/s

The calculation is as follows:

KE = rac{1}{2} imes 0.046 imes (3.5)^2 = 0.28 ext{ J}

Step 4

Use Figure 7 to estimate the maximum height that the ball reaches after the first bounce.

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Answer

By observing Figure 7, the maximum height reached after the first bounce is estimated to be between 0.8 m and 0.95 m.

Step 5

Explain why the ball does not bounce back to its starting height of 2.05 m.

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Answer

The ball does not return to its starting height of 2.05 m because energy is lost during each bounce. This loss can be due to various factors such as:

  1. Energy being transferred to the surroundings (sound, thermal energy).
  2. The system not being 100% efficient.
  3. The bounce being non-elastic.

Step 6

Describe how the maximum height reached changes with the bounce number in Figure 8.

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Answer

As the bounce number increases, the maximum height reached decreases. There is a negative correlation observed between the bounce number and maximum height, indicating a non-linear relationship.

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