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a) Solid, liquid and gas are states of matter - Edexcel - GCSE Physics Combined Science - Question 4 - 2019 - Paper 1

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a) Solid, liquid and gas are states of matter. Which process describes the change from a solid to a liquid? b) A student determines the density of a liquid. The stu... show full transcript

Worked Solution & Example Answer:a) Solid, liquid and gas are states of matter - Edexcel - GCSE Physics Combined Science - Question 4 - 2019 - Paper 1

Step 1

mass of liquid added = __________ g

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Answer

To calculate the mass of liquid added, subtract the mass of the empty measuring cylinder (201 g) from the mass after the liquid is added (230 g).

extMassofliquidadded=230extg201extg=29extg ext{Mass of liquid added} = 230 ext{ g} - 201 ext{ g} = 29 ext{ g}

Step 2

volume of liquid added = __________ cm³

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Answer

Since the density of the liquid is typically defined as mass/volume, and we have calculated the mass, we can ascertain that the volume added will also be equal to the mass added because the densities are equivalent in this context. Thus:

extVolumeofliquidadded=29extcm3 ext{Volume of liquid added} = 29 ext{ cm}^3

Step 3

Which equation should the student use to calculate the density of the liquid?

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Answer

To calculate the density of the liquid, the student should use option D:

ext{Density} = rac{ ext{mass}}{ ext{volume}}

Step 4

State two improvements the student could make to this investigation.

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Answer

  1. Use a balance that reads to one or more decimal places for more accurate mass measurements.
  2. Measure the liquid at eye level to avoid parallax error when reading the measuring cylinder.

Step 5

energy needed = __________ J

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Answer

To calculate the energy needed, we use the formula:

ΔQ=m×c×ΔθΔQ = m × c × Δθ

Substituting the values:

  • m = 1.5 kg
  • c = 4200 J/kg °C
  • Δθ = 50 °C

We get:

ΔQ=1.5imes4200imes50=315000extJΔQ = 1.5 imes 4200 imes 50 = 315000 ext{ J}

Step 6

time to bring the water to boiling point is __________ s

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Answer

To calculate the time, we can use the equation:

P = rac{E}{t}

Rearranging gives:

t = rac{E}{P}

Substituting the values:

  • E = 670000 J
  • P = 3500 W

Calculating:

t = rac{670000}{3500} = 191.43 ext{ s} ext{ (approximately 190 s)}

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