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An electric car is travelling at a speed of 16.0 m/s - Edexcel - GCSE Physics Combined Science - Question 5 - 2023 - Paper 2

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An electric car is travelling at a speed of 16.0 m/s. The total mass of the car is 1200 kg. (i) Calculate the kinetic energy, in kJ, of the car. (ii) On a journey... show full transcript

Worked Solution & Example Answer:An electric car is travelling at a speed of 16.0 m/s - Edexcel - GCSE Physics Combined Science - Question 5 - 2023 - Paper 2

Step 1

(i) Calculate the kinetic energy, in kJ, of the car.

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Answer

To find the kinetic energy (KE) of the car, we use the formula:

KE=12mv2KE = \frac{1}{2} mv^2

Where:

  • m = mass of the car = 1200 kg
  • v = speed of the car = 16.0 m/s

Substituting the values:

KE=12×1200×(16.0)2KE = \frac{1}{2} \times 1200 \times (16.0)^2

Calculating the result:

KE=12×1200×256=153600 JKE = \frac{1}{2} \times 1200 \times 256 = 153600 \text{ J}

To convert joules to kilojoules, divide by 1000:

KE=1536001000=153.6 kJKE = \frac{153600}{1000} = 153.6 \text{ kJ}

Thus, the kinetic energy of the car is approximately 154 kJ.

Step 2

(ii) Calculate the time taken for the battery to become discharged on this journey.

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Answer

To find the time taken (t) for the battery to become discharged, we use the relationship between energy (E), power (P), and time:

E=P×tE = P \times t

Rearranging for time, we have:

t=EPt = \frac{E}{P}

Here:

  • E = total energy transferred = 126 MJ = 126 \times 10^6 J
  • P = power = 17.5 kW = 17.5 \times 10^3 W

Substituting the values into the equation:

t=126×10617.5×103t = \frac{126 \times 10^6}{17.5 \times 10^3}

Calculating:

t=126000000175007200 st = \frac{126000000}{17500} \approx 7200 \text{ s}

To convert seconds into hours, divide by 3600:

t72003600=2 hourst \approx \frac{7200}{3600} = 2 \text{ hours}

Thus, the time taken for the battery to become discharged is 2 hours.

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