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5 (a) Figure 10 shows two different types of the same circuit component - Edexcel - GCSE Physics Combined Science - Question 5 - 2021 - Paper 1

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5 (a) Figure 10 shows two different types of the same circuit component. What is the name of this circuit component? A diode B light dependent resistor C thermis... show full transcript

Worked Solution & Example Answer:5 (a) Figure 10 shows two different types of the same circuit component - Edexcel - GCSE Physics Combined Science - Question 5 - 2021 - Paper 1

Step 1

What is the name of this circuit component?

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Answer

The circuit component in Figure 10 is a thermistor. A thermistor is a type of resistor whose resistance varies significantly with temperature.

Step 2

Which row in the table describes the way that ammeters and voltmeters should be connected with a component in a circuit?

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Answer

The correct way to connect an ammeter and a voltmeter in a circuit is given in Row C:

  • Ammeter: in series
  • Voltmeter: in parallel. This configuration ensures that the ammeter measures the current flowing through the component and the voltmeter measures the potential difference across it.

Step 3

Describe the relationship between the current and the voltage as shown in the graph in Figure 11.

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The graph in Figure 11 illustrates a nonlinear relationship between current and voltage. As voltage increases, the current also increases, but not in a linear manner. Initially, at lower voltage values, current rises gradually, indicating ohmic behavior, but as the voltage reaches higher levels, the current increases at an accelerated rate. This suggests that the filament lamp exhibits properties of a non-ohmic component, where resistance changes with temperature.

Step 4

Use the values of the voltage and current at point P and at point Q on the graph in Figure 11 to complete the table in Figure 12.

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Answer

voltage in Vcurrent in mA
point P2.0
point Q4.0

Step 5

Calculate the resistance of the filament lamp when the voltage is 4.5 V and the current is 51 mA.

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Answer

To calculate the resistance, we use the formula: R=VIR = \frac{V}{I} Substituting the known values: R=4.551×103R = \frac{4.5}{51 \times 10^{-3}} Performing the calculation: R=88.24ΩR = 88.24 \, \Omega Therefore, the resistance of the filament lamp is approximately 88.2 Ω.

Step 6

Explain why the resistance of the filament lamp changes as the voltage across it increases.

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Answer

As voltage increases across the filament lamp, the temperature of the filament rises due to the increased electrical power being supplied. Since the filament is made of a metal, it exhibits a positive temperature coefficient of resistance, meaning that as its temperature increases, its resistance also increases. Consequently, at higher voltages, the increase in filament temperature results in higher resistance, leading to a nonlinear current-voltage relationship.

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