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6 (a) An electric kettle contains 1.41 kg of water at 25°C - Edexcel - GCSE Physics Combined Science - Question 6 - 2021 - Paper 1

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6 (a) An electric kettle contains 1.41 kg of water at 25°C. The kettle is switched on. After a while, the kettle reaches boiling point at 100°C. The specific heat... show full transcript

Worked Solution & Example Answer:6 (a) An electric kettle contains 1.41 kg of water at 25°C - Edexcel - GCSE Physics Combined Science - Question 6 - 2021 - Paper 1

Step 1

Calculate the amount of thermal energy supplied to the water by the kettle.

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Answer

To calculate the thermal energy supplied to the water, we use the equation:

Q=mimescimesriangleT Q = m imes c imes riangle T

Where:

  • QQ is the thermal energy (J)
  • mm is the mass of water (kg)
  • cc is the specific heat capacity (J/kg°C)
  • riangleT riangle T is the change in temperature (°C)

Substituting the values:

  • m=1.41m = 1.41 kg
  • c=4200c = 4200 J/kg°C
  • riangleT=10025=75 riangle T = 100 - 25 = 75 °C

Then we find:

Q=1.41imes4200imes75=444150extJQ = 1.41 imes 4200 imes 75 = 444150 ext{ J}

Therefore, the thermal energy supplied to the water is approximately 444000 J (to 3 significant figures).

Step 2

Calculate the specific latent heat of vaporisation of water.

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Answer

For the specific latent heat of vaporisation, we use the formula:

L=QmL = \frac{Q}{m}

Where:

  • LL is the specific latent heat of vaporisation (J/kg)
  • QQ is the thermal energy supplied (J)
  • mm is the mass of the water that has evaporated (kg)

Given:

  • Q=450000Q = 450000 J
  • m=1.411.21=0.2m = 1.41 - 1.21 = 0.2 kg

Substituting the numbers:

L=4500000.2=2250000extJ/kgL = \frac{450000}{0.2} = 2250000 ext{ J/kg}

Thus, the specific latent heat of vaporisation of water is 2250000 J/kg.

Step 3

Describe how a student could use this apparatus, and any additional items needed, to determine the specific heat capacity of aluminium.

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Answer

To determine the specific heat capacity of aluminium, the student could follow these steps:

  1. Measure the temperature of the boiling water:

    • Use a thermometer to accurately measure and record the boiling point of the water.
  2. Allow sufficient time for the block to reach temperature of boiling water:

    • Place the aluminium block in the boiling water for a sufficient period to ensure it reaches equilibrium temperature with the water.
  3. Measure temperature of cold water:

    • Before transferring the block, measure the initial temperature of the cold water using a thermometer.
  4. Transfer the aluminium block to the cold water:

    • Using the piece of string, carefully transfer the hot aluminium block to the beaker of cold water without loss of heat.
  5. Record temperature changes:

    • Continuously monitor the temperature of the cold water until it stabilizes. Record the final temperature of the cold water.
  6. Calculate the specific heat capacity of aluminium:

    • Use the formula:
    Qlost=QgainedQ_{lost} = Q_{gained}

    to find the heat transferred. Calculate the heat lost by the aluminium block using:

    mAlimescAlimes(TinitialTfinal)=mwaterimescwaterimes(TfinalTinitial,cold)m_{Al} imes c_{Al} imes (T_{initial} - T_{final}) = m_{water} imes c_{water} imes (T_{final} - T_{initial, cold})

The specific heat capacity cAlc_{Al} can then be solved, rearranging as needed based on the measurements taken.

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