Photo AI

5. (a) Which of these describes isotopes of an element? A same atomic number different number of neutrons B same atomic number different number of protons C same mass number different number of neutrons D same mass number different number of protons (b) Figure 7 represents a decay that can happen inside the nucleus of an atom - Edexcel - GCSE Physics Combined Science - Question 5 - 2020 - Paper 1

Question icon

Question 5

5.-(a)-Which-of-these-describes-isotopes-of-an-element?--A-same-atomic-number-different-number-of-neutrons-B-same-atomic-number-different-number-of-protons-C-same-mass-number-different-number-of-neutrons-D-same-mass-number-different-number-of-protons--(b)-Figure-7-represents-a-decay-that-can-happen-inside-the-nucleus-of-an-atom-Edexcel-GCSE Physics Combined Science-Question 5-2020-Paper 1.png

5. (a) Which of these describes isotopes of an element? A same atomic number different number of neutrons B same atomic number different number of protons C same ma... show full transcript

Worked Solution & Example Answer:5. (a) Which of these describes isotopes of an element? A same atomic number different number of neutrons B same atomic number different number of protons C same mass number different number of neutrons D same mass number different number of protons (b) Figure 7 represents a decay that can happen inside the nucleus of an atom - Edexcel - GCSE Physics Combined Science - Question 5 - 2020 - Paper 1

Step 1

Which of these describes isotopes of an element?

96%

114 rated

Answer

Isotopes are variants of a chemical element that have the same number of protons (same atomic number) but different numbers of neutrons. Therefore, the correct answer is 'A: same atomic number, different number of neutrons.'

Step 2

Which decay is represented in Figure 7?

99%

104 rated

Answer

Figure 7 indicates a beta minus decay, where a neutron in the nucleus decays into a proton and an electron (beta particle) is emitted. Thus, the answer is 'beta minus'.

Step 3

Estimate the activity of this source in the year 2020.

96%

101 rated

Answer

To find the activity of the cobalt source in the year 2020, we use the half-life of cobalt-60, which is 5 years. Since the year 2000 has a starting activity of 38.5 kBq, and from 2000 to 2020 is 20 years, that means there are 4 half-lives:

  1. Calculate the activity after each half-life:
    • After 1 half-life (2005): 38.5 kBq÷2=19.25 kBq38.5 \text{ kBq} \div 2 = 19.25 \text{ kBq}
    • After 2 half-lives (2010): 19.25 kBq÷2=9.625 kBq19.25 \text{ kBq} \div 2 = 9.625 \text{ kBq}
    • After 3 half-lives (2015): 9.625 kBq÷2=4.8125 kBq9.625 \text{ kBq} \div 2 = 4.8125 \text{ kBq}
    • After 4 half-lives (2020): 4.8125 kBq÷2=2.40625 kBq4.8125 \text{ kBq} \div 2 = 2.40625 \text{ kBq}

Thus, the estimated activity in the year 2020 is approximately 2.41 kBq.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;