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1 (a) Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in direction of force C work done = force × distance moved at right angles to direction of force D work done = force × distance moved at right angles to direction of force (b) A ball has a mass of 0.046 kg - Edexcel - GCSE Physics: Combined Science - Question 1 - 2019 - Paper 1

Question 1

1-(a)-Which-of-these-is-the-equation-for-work-done?----A---work-done-=-force-÷-distance-moved-in-direction-of-force-B---work-done-=-force-×-distance-moved-in-direction-of-force-C---work-done-=-force-×-distance-moved-at-right-angles-to-direction-of-force-D---work-done-=-force-×-distance-moved-at-right-angles-to-direction-of-force--(b)-A-ball-has-a-mass-of-0.046-kg-Edexcel-GCSE Physics: Combined Science-Question 1-2019-Paper 1.png

1 (a) Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in directi... show full transcript

Worked Solution & Example Answer:1 (a) Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in direction of force C work done = force × distance moved at right angles to direction of force D work done = force × distance moved at right angles to direction of force (b) A ball has a mass of 0.046 kg - Edexcel - GCSE Physics: Combined Science - Question 1 - 2019 - Paper 1

Step 1

Which of these is the equation for work done?

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Answer

The correct answer is B: work done = force × distance moved in direction of force. This equation states that work is the product of the force applied to an object and the distance that the object moves in the direction of that force.

Step 2

Calculate the change in gravitational potential energy when the ball is lifted through a vertical height of 2.05 m.

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Answer

To calculate the change in gravitational potential energy (ΔGPE), we use the formula:

ΔGPE = m × g × Δh

Where:

m = mass of the ball = 0.046 kg
g = acceleration due to gravity ≈ 9.81 m/s²
Δh = height lifted = 2.05 m

Now substituting the values:

ΔGPE = 0.046 imes 9.81 imes 2.05

Calculating this gives:

ΔGPE ≈ 0.92 ext{ J}

Step 3

Calculate the kinetic energy of the ball when the speed of the ball is 3.5 m/s.

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Answer

To find the kinetic energy (KE) of the ball, we use the formula:

KE = \frac{1}{2} m v^2

Where:

m = 0.046 kg (mass of the ball)
v = 3.5 m/s (speed of the ball)

Substituting these values into the equation:

KE = \frac{1}{2} (0.046) (3.5)^2

Calculating the square:

KE = \frac{1}{2} (0.046) (12.25)

After calculations:

KE ≈ 0.281 ext{ J} ext{ or } 0.28 ext{ J (rounded)}

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