A car is travelling along a level road. (i) Complete the sentence by putting a cross (X) in the box next to your answer. When the velocity of the car is constant, the force of friction on it is: ☐ A zero ☐ B greater than the driving force ☐ C smaller than the driving force ☐ D the same size as the driving force (ii) The car now accelerates in a straight line. Its average acceleration is 12 m/s². Calculate the increase in velocity of the car in 4.0 s. speed = __________ m/s

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A car is travelling along a level road - Edexcel - GCSE Physics - Question 5 - 2013 - Paper 1

Question 5

A car is travelling along a level road. (i) Complete the sentence by putting a cross (X) in the box next to your answer. When the velocity of the car is constant, ... show full transcript

Worked Solution & Example Answer:A car is travelling along a level road - Edexcel - GCSE Physics - Question 5 - 2013 - Paper 1

Step 1

Complete the sentence by putting a cross (X) in the box next to your answer.

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Answer

When the velocity of the car is constant, the force of friction on it is D - the same size as the driving force. This is because, at constant velocity, the forces acting on the car are balanced, meaning the driving force and the force of friction are equal.

Step 2

Calculate the increase in velocity of the car in 4.0 s.

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Answer

To calculate the increase in velocity, we can use the formula:

v = a imes t

where:

$v$ is the increase in velocity,
$a$ is the acceleration (12 m/s²),
$t$ is the time (4.0 s).

Substituting the values:

v = 12 ext{ m/s}² imes 4.0 ext{ s} = 48 ext{ m/s}

Therefore, the increase in velocity of the car is 48 m/s.

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