Figure 3 shows the parts in an electrical circuit - Edexcel - GCSE Physics - Question 2 - 2023 - Paper 2

Given:

• Current, $I = 0.46 \, A$
• Time, $t = 30 \, s$

Using the formula:

$$Q = I \times t$$

Substituting the values:

$$Q = 0.46 \, A \times 30 \, s = 13.8 \, C$$

Thus, the total charge that flows through the lamp in 30 seconds is 13.8 C.

Given:

• Current, $I = 0.46 \, A$
• Voltage, $V = 6.0 \, V$
• Time, $t = 60 \, s$ (1 minute)

Using the formula:

$$E = I \times V \times t$$

Substituting the values:

$$E = 0.46 \, A \times 6.0 \, V \times 60 \, s$$

Calculating:

$$E = 0.46 \times 6.0 \times 60 = 165.6 \, J$$

Thus, the energy transferred to the lamp in one minute is approximately 166 J.