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A student uses this circuit to investigate how the current in a filament lamp varies with the potential difference (voltage) across the lamp - Edexcel - GCSE Physics - Question 5 - 2016 - Paper 1

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A student uses this circuit to investigate how the current in a filament lamp varies with the potential difference (voltage) across the lamp. (a) Add a voltmeter to... show full transcript

Worked Solution & Example Answer:A student uses this circuit to investigate how the current in a filament lamp varies with the potential difference (voltage) across the lamp - Edexcel - GCSE Physics - Question 5 - 2016 - Paper 1

Step 1

Add a voltmeter to the circuit that can be used to measure the potential difference (voltage) across the lamp.

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Answer

To measure the potential difference across the lamp, the voltmeter should be connected in parallel with the lamp.

Step 2

Complete the sentence by putting a cross (✗) in the box next to your answer.

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Answer

The correct answer is: A

  • 12 joules per coulomb.

Step 3

When the variable resistor is at the halfway position, the ammeter reads 0.37 A and the voltmeter reads 40 V. Show that the resistance of the filament in the lamp is about 11 Ω.

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Answer

Using Ohm’s Law, where resistance (R) is calculated as:

R=VIR = \frac{V}{I}

Substituting the given values:

R=40 V0.37 AR = \frac{40 \text{ V}}{0.37 \text{ A}}

Calculating this, we find:

R108.11Ω11ΩR \approx 108.11 \Omega \approx 11 \Omega.

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