The students took five results for the left hand and five results for the right hand - Edexcel - GCSE Physics - Question 6 - 2016 - Paper 1
Question 6
The students took five results for the left hand and five results for the right hand.
Figure 5 shows their results.
which hand rials 1 trials 2 trials 3 trials 4 tr... show full transcript
Worked Solution & Example Answer:The students took five results for the left hand and five results for the right hand - Edexcel - GCSE Physics - Question 6 - 2016 - Paper 1
Step 1
Calculate the average distance dropped for the right hand.
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Answer
To find the average distance dropped for the right hand, we need to sum all the distances dropped in each trial and divide by the number of trials.
The distances dropped are as follows:
Trial 1: 17.5 cm
Trial 2: 16.1 cm
Trial 3: 19.4 cm
Trial 4: 18.6 cm
Trial 5: 20.2 cm
Calculating the total distance dropped:
extTotal=17.5+16.1+19.4+18.6+20.2=91.8extcm
Now, divide the total by the number of trials (5):
extAverage=591.8=18.36extcm
To give the answer to 2 significant figures, we round 18.36 to 18 cm.
Step 2
Calculate the average time for the left hand.
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Answer
To calculate the average time for the left hand, we can use the relationship defined by the equation:
exttime2=extdistance
We will use the average distance dropped for the left hand. According to Figure 5, the average for the left hand is 14 cm. Plugging this value into the equation:
exttime2=14extcm
Now, taking the square root to solve for time:
exttime=extsqrt(14)exts≈3.74exts
Thus, the average time for the left hand is approximately 3.74 s.