Figure 17 shows a football kicked against a wall - Edexcel - GCSE Physics - Question 9 - 2023 - Paper 1

To calculate the height at which the ball hits the wall, we start with the equation for gravitational potential energy (GPE):

$\Delta GPE = m \times g \times \Delta h$

Given:

• Change in gravitational potential energy, (\Delta GPE = 11 J)
• Mass of the football, (m = 0.42 kg)
• Gravitational field strength, (g = 10 N/kg)

We can rearrange the formula to solve for height, (\Delta h):

$\Delta h = \frac{\Delta GPE}{m \times g}$

Substituting in the values:

$\Delta h = \frac{11 J}{0.42 kg \times 10 N/kg}$

Calculating gives:

$\Delta h = \frac{11}{4.2} \approx 2.62 m$

Thus, the height at which the ball hits the wall is approximately 2.62 m.