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Figure 14 shows a spring standing on a table - Edexcel - GCSE Physics - Question 6 - 2020 - Paper 1

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Figure 14 shows a spring standing on a table. Weights are added to the spring as shown in Figures 14b and 14c. (a) (i) Estimate the original length of the spring as... show full transcript

Worked Solution & Example Answer:Figure 14 shows a spring standing on a table - Edexcel - GCSE Physics - Question 6 - 2020 - Paper 1

Step 1

Estimate the original length of the spring as shown in Figure 14a.

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Answer

To estimate the original length of the spring from Figure 14a, observe the position of the top coil of the spring relative to a scale. It appears to be between 50.0 mm and 55.0 mm. Therefore, the original length of the spring is approximately 52.5 mm, acknowledging that it could range inclusively within these values.

Step 2

Describe the method used to estimate the original length of the spring.

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Answer

To estimate the original length of the spring, follow these steps:

  1. Place the spring upright on a flat surface, ensuring it is not compressed.
  2. Use a ruler with millimeter divisions to measure the length of the spring from the bottom to the top coil.
  3. Ensure that your eye is level with the measurement point to prevent parallax error.
  4. Record the measurement for accuracy.

Step 3

State two ways that the experimental procedure could be improved.

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Answer

  1. Use a ruler with a finer measurement division to enhance accuracy in length readings.
  2. Take multiple readings and average them to minimize the effect of random errors in measurement.

Step 4

Give one reason why the reduction in length eventually reaches a limit as more weights are added.

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Answer

The reduction in length reaches a limit because the coils of the spring are pushed together and eventually touch, meaning no further extension can occur regardless of additional weight.

Step 5

Calculate the spring constant k in N/m.

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Answer

To find the spring constant k, use Hooke's law, which is expressed as: k=Fxk = \frac{F}{x} Where:

  • F = 0.5 N (force applied)
  • x = 13 mm = 0.013 m (extension in meters)

Substituting the values: k=0.50.013=38.46 N/mk = \frac{0.5}{0.013} = 38.46 \text{ N/m} Thus, the spring constant k is approximately 38.5 N/m.

Step 6

Calculate the extension of the spring.

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Answer

To calculate the extension of the spring, we can use the work-energy principle: E=12kx2E = \frac{1}{2} k x^2 Where:

  • E = 0.14 J (work done)
  • k = 175 N/m (spring constant)

Rearrange the equation for x: x2=2Ekx^2 = \frac{2E}{k} Then, x2=2×0.14175x^2 = \frac{2 \times 0.14}{175} Calculating yields: x2=0.0016x^2 = 0.0016 Thus, x = √(0.0016) = 0.04 m. Therefore, the extension of the spring is 0.04 m.

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