Figure 10 shows a toy used to launch a ball - Edexcel - GCSE Physics - Question 4 - 2020 - Paper 1
Question 4
Figure 10 shows a toy used to launch a ball.
One end of the spring is fixed to the handle.
The other end of the spring is fixed to the support.
(a) A child pulls th... show full transcript
Worked Solution & Example Answer:Figure 10 shows a toy used to launch a ball - Edexcel - GCSE Physics - Question 4 - 2020 - Paper 1
Step 1
Which of these shows the forces acting on the handle when the child keeps the spring stretched?
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Answer
To determine which diagram illustrates the forces on the handle, it's important to consider the situation. A child pulling on the handle stretches the spring, putting tension in the spring and a force upwards due to the handle against the downward force of the child's pull. The correct diagram should illustrate these two equal and opposite forces.
Step 2
Calculate the force used to extend the spring.
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Answer
Using the equation:
extforce=kimesextextension
Substituting the values:
Spring constant, k=20extN/m
Extension, 0.070extm
We find:
extforce=20imes0.070=1.4extN
Step 3
Calculate the work done in extending the spring by 0.09m.
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Answer
Using the work done equation:
ext{work done} = rac{1}{2} imes k imes ( ext{extension})^2
Describe the energy transfer that takes place when the ball starts to move.
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Answer
When the child lets go of the handle, the potential energy stored in the stretched spring is converted into kinetic energy as the spring returns to its original shape. This energy transfer initiates the motion of the ball, converting potential energy into kinetic energy as the ball starts to move. As the ball moves, some kinetic energy may also be transferred to the surroundings, manifesting in sound and heat energy.
Step 5
Explain how the design of the toy prevents the spring from becoming damaged.
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Answer
The design ensures that the spring can only be stretched until the pad is in contact with the support, effectively controlling the maximum extension. This prevents over-stretching, which could damage the spring. By maintaining the spring within its elastic limit, it avoids being permanently deformed or broken.