This question is about using the mains electricity supply - Edexcel - GCSE Physics - Question 5 - 2021 - Paper 1

To calculate the energy transferred, we use the equation:

$E = I \times V \times t$

Substituting in the values:

$E = 7.4 \times 230 \times 120$

Calculating this results in:

$E = 203280 \text{ J}$

The energy transferred to the coffee machine is approximately 200,000 J.

Wire X = neutral Wire Y = live

Component Z = fuse

Using the efficiency equation:

$\text{input current} \times \text{input voltage} = \text{output current} \times \text{output voltage}$

Substituting the known values:

$\text{input current} \times 230 = 2.37 \times 190$

Calculating:

$\text{input current} = \frac{2.37 \times 190}{230}$

This gives:

$\text{input current} \approx 1.9 \text{ A}$