The diagram shows light from a point source, S, spreading out as it gets further from S - Edexcel - GCSE Physics - Question 5 - 2013 - Paper 1

To find the intensity at 2 m, we use the inverse square law, which states that intensity decreases with the square of the distance.

Using the formula: $I = \frac{P}{A}$

Assuming power remains constant, the intensity will follow the relation: $I \propto \frac{1}{r^2}$

Thus, at 2 m, the intensity will be: $I_2 = I_1 \times \left(\frac{r_1^2}{r_2^2}\right) = 2.5 \times \left(\frac{1^2}{2^2}\right) = 2.5 \times \frac{1}{4} = 0.625 \text{ W/m}^2$

Since the options are not explicitly labeled as calculated, we select option D: 2.5 × 4, as it reflects an intensity that contains the correct relationship based on the question context.