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The students took five results for the left hand and five results for the right hand - Edexcel - GCSE Physics - Question 6 - 2016 - Paper 1
Question 6
The students took five results for the left hand and five results for the right hand. Figure 5 shows their results. which hand rials 1 trials 2 trials 3 trials 4 tr... show full transcript
Worked Solution & Example Answer:The students took five results for the left hand and five results for the right hand - Edexcel - GCSE Physics - Question 6 - 2016 - Paper 1
Step 1
Calculate the average distance dropped for the right hand.
Answer
To calculate the average distance dropped for the right hand, sum the distances and divide by the number of trials:
- Distance values for the right hand: 17.5 cm, 16.1 cm, 19.4 cm, 18.6 cm, 20.2 cm.
- Sum of distances = 17.5 + 16.1 + 19.4 + 18.6 + 20.2 = 91.8 cm.
- Number of trials = 5.
- Average = ( \frac{91.8 \text{ cm}}{5} = 18.36 \text{ cm} ). Thus, the average distance dropped, correct to 2 significant figures, is 18 cm.
Step 2
Calculate the average time for the left hand.
Answer
To calculate the average time for the left hand, we first need to find the average distance dropped. The distances for the left hand are: 10.1 cm, 25.5 cm, 18.4 cm, 14.6 cm, and 11.7 cm.
Calculating the average:
- Sum of distances = 10.1 + 25.5 + 18.4 + 14.6 + 11.7 = 90.3 cm.
- Number of trials = 5.
- Average distance = ( \frac{90.3 \text{ cm}}{5} = 18.06 \text{ cm} ).
Next, using the equation for calculating time: ( \text{distance}^2 = \text{time} \times \text{(constant value)} ) (assumed constant for the scenario if given or inferred). Once the constant is known, rearranging for time gives: ( \text{time} = \frac{\text{distance}^2}{\text{constant value}} ). For average distance calculated above, further specifics are needed to compute time.