Figure 17 shows a football kicked against a wall. The football has a mass of 0.42 kg. (i) The football gains 11 J of gravitational potential energy as it moves from the ground to the wall. Calculate the height at which the ball hits the wall. Gravitational field strength = 10 N/kg Use the equation ΔGPE = m × g × Δh height = _________________ m (ii) Calculate the kinetic energy of the football when it is moving at a velocity of 12 m/s. Use the equation KE = \frac{1}{2} m × v^2.

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Figure 17 shows a football kicked against a wall - Edexcel - GCSE Physics - Question 9 - 2023 - Paper 1

Question 9

Figure 17 shows a football kicked against a wall. The football has a mass of 0.42 kg. (i) The football gains 11 J of gravitational potential energy as it moves fro... show full transcript

Worked Solution & Example Answer:Figure 17 shows a football kicked against a wall - Edexcel - GCSE Physics - Question 9 - 2023 - Paper 1

Step 1

Calculate the height at which the ball hits the wall.

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Answer

To find the height, we can rearrange the gravitational potential energy equation:

$\Delta GPE = m \times g \times \Delta h$

Substituting in the values:

ΔGPE = 11 J
m = 0.42 kg
g = 10 N/kg

We have:

$11 = 0.42 \times 10 \times \Delta h$

Simplifying gives:

$\Delta h = \frac{11}{0.42 \times 10}$

Calculating:

$\Delta h = \frac{11}{4.2} \approx 2.62 \, \text{m}$

Step 2

Calculate the kinetic energy of the football when it is moving at a velocity of 12 m/s.

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Answer

Using the kinetic energy formula:

$KE = \frac{1}{2} m \times v^2$

Substituting in the values:

m = 0.42 kg
v = 12 m/s

We have:

$KE = \frac{1}{2} \times 0.42 \times (12)^2$

Calculating:

$KE = 0.21 \times 144 = 30.24 \, J$

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