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Figure 14 shows a spring standing on a table - Edexcel - GCSE Physics - Question 6 - 2020 - Paper 1

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Figure 14 shows a spring standing on a table. Weights are added to the spring as shown in Figures 14b and 14c. (a) (i) Estimate the original length of the spring a... show full transcript

Worked Solution & Example Answer:Figure 14 shows a spring standing on a table - Edexcel - GCSE Physics - Question 6 - 2020 - Paper 1

Step 1

Estimate the original length of the spring as shown in Figure 14a.

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Answer

The original length of the spring can be estimated visually by measuring the position of the top of the spring in Figure 14a using a ruler. It appears to be between 50.0 mm and 55.0 mm.

Step 2

Describe the method used to determine the original length of the spring.

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Answer

To determine the original length of the spring, follow these steps:

  1. Use a ruler with small divisions to measure the spring length accurately.
  2. Align the ruler correctly alongside the spring without any parallax error.
  3. Take multiple readings to reduce measurement error and average the results for accuracy.

Step 3

State two ways that the experimental procedure could be improved.

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Answer

  1. Use a ruler with smaller millimeter divisions for more precise measurements.
  2. Perform the measurement at eye level to avoid parallax error.

Step 4

Give one reason why the reduction in length eventually reaches a limit as more weights are added.

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Answer

The reduction in length eventually reaches a limit because the coils of the spring become fully compressed, preventing any further extension.

Step 5

Calculate the spring constant k in N/m.

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Answer

Use Hooke's Law, which states that the force (F) is equal to the spring constant (k) multiplied by the extension (x):

F=kimesxF = k imes x Substituting the given values:

0.5=kimes(13imes103)0.5 = k imes (13 imes 10^{-3}) Rearranging gives:

k=0.513×103=38.46 N/mk = \frac{0.5}{13 \times 10^{-3}} = 38.46 \text{ N/m}

Step 6

Calculate the extension of the spring.

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Answer

The work done on the spring can be calculated using:

E=12kx2E = \frac{1}{2} k x^2 Rearranging gives:

x2=2Ekx^2 = \frac{2E}{k} Substituting the given values:

x2=2×0.14175x^2 = \frac{2 \times 0.14}{175} Calculating the extension:

x2=0.28175=0.0016x^2 = \frac{0.28}{175} = 0.0016 Therefore,

x=0.0016=0.04 mx = \sqrt{0.0016} = 0.04 \text{ m}

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