Photo AI

1. The picture shows a weight lifter - Edexcel - GCSE Physics - Question 1 - 2012 - Paper 1

Question icon

Question 1

1.-The-picture-shows-a-weight-lifter-Edexcel-GCSE Physics-Question 1-2012-Paper 1.png

1. The picture shows a weight lifter. (a) In one lift, he does 5040 J of work against gravity. (i) One lift takes 4 seconds. Complete the sentence by putting a cr... show full transcript

Worked Solution & Example Answer:1. The picture shows a weight lifter - Edexcel - GCSE Physics - Question 1 - 2012 - Paper 1

Step 1

Complete the sentence

96%

114 rated

Answer

To calculate power, we use the formula:

P=WtP = \frac{W}{t}

Where:

  • PP is the power in watts (W)
  • WW is the work done in joules (J)
  • tt is the time in seconds (s)

Substituting the given values:

P=5040J4s=1260WP = \frac{5040 \, \text{J}}{4 \, \text{s}} = 1260 \, \text{W}

Thus, the correct option is A 1260 W.

Step 2

Calculate the height he lifts this mass

99%

104 rated

Answer

First, we calculate the weight of the mass using the formula:

F=mgF = m \cdot g

Where:

  • FF is the force (weight) in newtons (N)
  • mm is the mass in kilograms (kg)
  • gg is the gravitational field strength (N/kg)

Substituting the values:

F=240kg10N/kg=2400NF = 240 \, \text{kg} \cdot 10 \, \text{N/kg} = 2400 \, \text{N}

Since the energy gained by the mass is equal to the work done, we set the work done to the weight lifted multiplied by the height:

W=FhW = F \cdot h

Given that W=5040JW = 5040 \, \text{J}, we solve for height (hh):

h=WF=5040J2400N=2.1mh = \frac{W}{F} = \frac{5040 \, \text{J}}{2400 \, \text{N}} = 2.1 \, \text{m}

Thus, the height he lifts this mass is 2.1 m.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;