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Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in direction of force C work done = force × distance moved at right angles to direction of force D work done = force × distance moved at right angles to direction of force (b) A ball has a mass of 0.046kg - Edexcel - GCSE Physics - Question 2 - 2019 - Paper 1

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Which-of-these-is-the-equation-for-work-done?--A-work-done-=-force-÷-distance-moved-in-direction-of-force--B-work-done-=-force-×-distance-moved-in-direction-of-force--C-work-done-=-force-×-distance-moved-at-right-angles-to-direction-of-force--D-work-done-=-force-×-distance-moved-at-right-angles-to-direction-of-force---(b)-A-ball-has-a-mass-of-0.046kg-Edexcel-GCSE Physics-Question 2-2019-Paper 1.png

Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in direction of force... show full transcript

Worked Solution & Example Answer:Which of these is the equation for work done? A work done = force ÷ distance moved in direction of force B work done = force × distance moved in direction of force C work done = force × distance moved at right angles to direction of force D work done = force × distance moved at right angles to direction of force (b) A ball has a mass of 0.046kg - Edexcel - GCSE Physics - Question 2 - 2019 - Paper 1

Step 1

Which of these is the equation for work done?

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Answer

The correct equation for work done is:

B work done = force × distance moved in direction of force.

Step 2

Calculate the change in gravitational potential energy when the ball is lifted through a vertical height of 2.05m.

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Answer

To calculate the change in gravitational potential energy (

∆GPE), we can use the formula:

ΔGPE=m×g×Δh\Delta GPE = m \times g \times \Delta h

Where:

  • m is the mass of the ball (0.046 kg)
  • g is the acceleration due to gravity (approximately 9.81 m/s²)
  • Δh is the height (2.05 m)

Now, substituting the values:

ΔGPE=0.046×9.81×2.05\Delta GPE = 0.046 \times 9.81 \times 2.05

Calculating this gives:

ΔGPE=0.046×9.81×2.050.93 J\Delta GPE = 0.046 \times 9.81 \times 2.05 \approx 0.93 \text{ J}

Therefore, the change in gravitational potential energy is approximately 0.93 J.

Step 3

Calculate the kinetic energy of the ball when the speed of the ball is 3.5m/s.

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Answer

The formula for kinetic energy (KE) is given by:

KE=12mv2KE = \frac{1}{2} m v^2

Where:

  • m is the mass of the ball (0.046 kg)
  • v is the speed of the ball (3.5 m/s)

Substituting in the values:

KE=12×0.046×(3.5)2KE = \frac{1}{2} \times 0.046 \times (3.5)^2

Calculating this gives:

KE=12×0.046×12.250.28 JKE = \frac{1}{2} \times 0.046 \times 12.25 \approx 0.28 \text{ J}

Thus, the kinetic energy of the ball when its speed is 3.5 m/s is approximately 0.28 J.

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