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4 (a) (i) Which lens is a converging lens with the greatest power? A B C D (ii) The equation that relates the power of a lens to the focal length of the lens is power (in dioptres) = \frac{1}{focal \ length \ (in \ metres)} The power of a lens is 5 dioptres - Edexcel - GCSE Physics - Question 4 - 2019 - Paper 1

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4-(a)-(i)-Which-lens-is-a-converging-lens-with-the-greatest-power?--A-B-C-D--(ii)-The-equation-that-relates-the-power-of-a-lens-to-the-focal-length-of-the-lens-is--power-(in-dioptres)-=-\frac{1}{focal-\-length-\-(in-\-metres)}--The-power-of-a-lens-is-5-dioptres-Edexcel-GCSE Physics-Question 4-2019-Paper 1.png

4 (a) (i) Which lens is a converging lens with the greatest power? A B C D (ii) The equation that relates the power of a lens to the focal length of the lens is p... show full transcript

Worked Solution & Example Answer:4 (a) (i) Which lens is a converging lens with the greatest power? A B C D (ii) The equation that relates the power of a lens to the focal length of the lens is power (in dioptres) = \frac{1}{focal \ length \ (in \ metres)} The power of a lens is 5 dioptres - Edexcel - GCSE Physics - Question 4 - 2019 - Paper 1

Step 1

Which lens is a converging lens with the greatest power?

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Answer

To determine which lens is a converging lens with the greatest power, we can assess the shape of each lens. A converging lens has two outwardly curved surfaces, which allow it to focus light to a point.

From the options given (A, B, C, D), the lens with the most pronounced curvature will have the greatest power. This is because the power of a lens is related to its curvature; a lens that is more curved will have a shorter focal length, resulting in higher power.

Without the actual images, one would typically choose option B or D (if one of them appears significantly more curved compared to the others), as these are usually designed to be converging and show greater convexity.

Step 2

Use the equation to calculate the focal length of the lens in cm.

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Answer

To find the focal length ( extit{f}) of the lens given that its power ( extit{P}) is 5 dioptres, we use the formula:

P=1fP = \frac{1}{f}

Rearranging this, we find:

f=1P=15=0.2 metresf = \frac{1}{P} = \frac{1}{5} = 0.2 \text{ metres}

To convert this value into centimeters, we multiply by 100:

0.2 metres×100=20 cm0.2 \text{ metres} \times 100 = 20 \text{ cm}

Thus, the focal length of the lens is:

focal length = 20 cm.

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