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(a) Which ray diagram shows total reflection at an air and glass boundary? (b) Figure 1 is a ray diagram for a converging lens when used as a magnifying glass - Edexcel - GCSE Physics - Question 1 - 2022 - Paper 1

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(a)-Which-ray-diagram-shows-total-reflection-at-an-air-and-glass-boundary?--(b)-Figure-1-is-a-ray-diagram-for-a-converging-lens-when-used-as-a-magnifying-glass-Edexcel-GCSE Physics-Question 1-2022-Paper 1.png

(a) Which ray diagram shows total reflection at an air and glass boundary? (b) Figure 1 is a ray diagram for a converging lens when used as a magnifying glass. (i)... show full transcript

Worked Solution & Example Answer:(a) Which ray diagram shows total reflection at an air and glass boundary? (b) Figure 1 is a ray diagram for a converging lens when used as a magnifying glass - Edexcel - GCSE Physics - Question 1 - 2022 - Paper 1

Step 1

Using information from Figure 1, determine the magnification of the virtual image.

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Answer

To determine the magnification ( ext{M}) of the virtual image, we use the formula:

M=height of imageheight of objectM = \frac{\text{height of image}}{\text{height of object}}

Assuming that the height of the virtual image is given as 'h_i' and the height of the object as 'h_o', plug in the values:

M=hihoM = \frac{h_i}{h_o}

The specific values should be extracted from Figure 1.

Step 2

Describe one way the magnification of the image could be increased.

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Answer

One way to increase the magnification is to use a different lens that has a higher power. A lens with a shorter focal length will result in a larger magnification. Specifically, switching to a stronger lens or a lens that is thicker and more curved will increase the magnification effectively.

Step 3

Calculate the focal length, f, of the lens.

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Answer

Using the provided data, we know:

  • a = 20 cm
  • b = 40 cm

Now, substituting these values into the equation:

1f=a+ba×b\frac{1}{f} = \frac{a+b}{a \times b}

Calculating:

1f=20+4020×40=60800=340\frac{1}{f} = \frac{20 + 40}{20 \times 40} = \frac{60}{800} = \frac{3}{40}

Thus, taking the reciprocal:

f=40313.33 cmf = \frac{40}{3} \approx 13.33 \text{ cm}

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