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Figure 3 shows the parts in an electrical circuit - Edexcel - GCSE Physics - Question 2 - 2023 - Paper 2

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Figure 3 shows the parts in an electrical circuit. The battery symbol and some of the connecting wires have been drawn for you. (c) (i) There is a current of 0.46 ... show full transcript

Worked Solution & Example Answer:Figure 3 shows the parts in an electrical circuit - Edexcel - GCSE Physics - Question 2 - 2023 - Paper 2

Step 1

Calculate the total charge that flows through the lamp in 30 seconds.

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Answer

To find the total charge (Q) that flows through the lamp, we can use the formula:

Q=IimestQ = I imes t

where:

  • II is the current in amperes (A), and
  • tt is the time in seconds (s).

Substituting in the values:

  • Current (II) = 0.46 A
  • Time (tt) = 30 s

Calculating: Q=0.46imes30=13.8extCQ = 0.46 imes 30 = 13.8 ext{ C}

Thus, the total charge that flows through the lamp in 30 seconds is 13.8 C.

Step 2

Calculate the energy transferred to the lamp in one minute.

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Answer

To calculate the energy transferred (E) to the lamp, we use the formula:

E=IimesVimestE = I imes V imes t

where:

  • II is the current in amperes (A),
  • VV is the voltage in volts (V), and
  • tt is the time in seconds (s).

Given:

  • Current (II) = 0.46 A
  • Voltage (VV) = 6.0 V
  • Time (tt) for one minute = 60 s

Substituting the values: E=0.46imes6.0imes60E = 0.46 imes 6.0 imes 60

Calculating: E=0.46imes6.0imes60=165.6extJE = 0.46 imes 6.0 imes 60 = 165.6 ext{ J}

Thus, the energy transferred to the lamp in one minute is approximately 170 J when rounded.

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